Correct Answer - A
AgBr shows both Schottky as well as Frenkel defect. In AgBr, both `Ag^(+)` and `Br^(-)` ions are absent from the lattice causing Schottky defect. However `Ag^(+)` ions are mobile so they have a tendency to move aside the lattice and trapped in interstitial site hence, cause F frendkel defect.