Correct Answer - [4]
`CH_(3)-CH_(2)-CH_(2)-CH=CH-CH_(3)rArr` cis and trans
`CH_(3)-CH_(2)-CH=CH-CH_(2)-CH_(3)rArr` cis and trans
`CH_(3)-CH_(2)-underset(CH_(3))underset(|)(C)=CH-CH_(3) rArr` cis and trans
`CH_(3)-underset(CH_(3))underset(|)(C)H-CH=CH-CH_(3)rArr` cis and trans