Correct Answer - A
D.U. in `C_(4)H_(7)C1=((2n_(C )+2)-(n_(H)+n_(C1)))/(2)`
`=(10-8)/(2)=1^(@)`
One `D.U` suggests that compound contains either one `(C=C)` bond or cyclic ring. Since acyclic isomers have been asked in the problem, the number of acyclic isomers, including stereoisomers, of `C_(4)H_(7)Cl` is :
Total acylic isomers including stereoisomers =12
