Question

If the solubility of `AgCl` in `0.1 M` NaCl is (`K_(sp)` of `AgCl = 1.2 xx 10^(-10)`)
A. 11
B. 9
C. 13
D. 5

Answer 1

Correct Answer - B
`K_(sp)` of `MOH = 1 xx 10^(-10) M^(2)`
`P^(H) = ?`
`MOH` is `AB` type of salt
`:. K_(SP) = S^(2)`
`[OH^(-)] = S`
`S = sqrt(K_(SP)) = sqrt(1 xx 10^(-18))`
`S = 10^(-5)`
`[OH^(-)] = 10^(-5)`
`P^(OH) = ="log"_(10)[OH^(-)] = - "log"_(10)10^(-5) = 5`
`P^(H) + P^(OH) = 14`
`:. P =14 - 5 = 9`