Calculate pH at which `Mg(OH)_(2)` begins to precipitate from a solution containing `0.10M Mg^(2+)` ions. `(K_(SP)of Mg(OH)_(2)=

When `Mg(OH)_(2)` starts precipitation, then
`[Mg^(2+)][OH^(-)]^(2)=K_(SP)of Mg(OH)_(2)`
`[0.1][OH^(-)]^(2)=1xx10^(-11)`
`:. [OH^(-)]=10^(-5)M`
`:. pOH=5`
`:. pH=14-pOH`
`pH=14-5=9`

Calculate pH at which `Mg(OH)_(2)` begins to precipitate from a solution containing `0.10M Mg^(2+)` ions. `(K_(SP)of Mg(OH)_(2)=1xx10^(-11))`

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