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Calculate K for the reaction, `A^(-)+H_(3)^(+)O hArr HA+H_(2)O`
if `K_(a)` value for the acid HA is `1.0xx10^(-6)`.
A. `1xx10^(-6)`
B. `1xx10^(12)`
C. `1xx10^(-12)`
D. `1xx10^(6)`

1 Answer

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Best answer
Correct Answer - D
`K_(a)=10^(-6)for HA+H_(2)OhArrH_(3)O^(+)A^(-)`
Thus K for reverse reaction is
`(1)/(10^(-6))=10^(6)`

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