Question

At `25^(@)C K_(b)` for `BOH=1.0xx10^(-12).0.01M` solution of `BOH` has `[OH^(-)]`:
A. `1.0xx10^(-6)M`
B. `1.0xx10^(-7)M`
C. `1.0xx10^(-5)M`
D. `2.0xx10^(-6)M`

Answer 1

Correct Answer - B
`[OH^(-)]=Calpha=Csqrt((K_(b))/(C ))`
`= sqrt((K_(b).C))= sqrt(1.0xx10^(-12)xx0.01)`
`=1.0xx10^(-7)M`