Correct Answer - A
Since `NaCI` is very concentated solution, so supression of ionisation of `NaCI` takes place in presence of `AgCI`, so the `AgCI` is more ionised and hence `AgCI` is more soluble in `NaCI`
`NaCI rarr Na^(o+) + CI^(Theta) AgCI rarr Ag^(o+) + CI^(Theta)`
