Correct Answer - A
If a reaction occurs in two steps, the equilibrium constant for the overall reaction is given by the product of the equilibrium constants for the individual steps.
`Ag^(o+) +NH_(3) hArr [Ag(NH_(3))]^(o+), K_(1) = 3.5 xx 10^(-3)`
`[Ag(NH)_(3)]^(o+) +NH_(3) hArr [Ag(NH_(3))_(2)]^(o+), K_(2) = 1.7 xx 10^(-3)`
`Ag^(o+) +2NH_(3) hArr [Ag(NH_(3))_(2)]^(o+)`,
Over all `K = K_(1) xx K_(2)`
`= 3.5 xx 10^(-3) xx 1.7 xx 10^(-3)`
`= 5.95 xx 10^(-6)`