Correct Answer - 2
`{:(,HCl,+,NaOHrarrNaCl,,+,H_(2)O),("Meq. before reaction",50xx0.6=30,,50xx0.3=15,0,,0),("Meq.after reaction",15,,0,15,,15):}`
For monovalent electrolysis`" " `Molarity =Normality `=("milli equivalent")/("total volume")`
`[Cl^(-)` provided by HCl and NaCl]
`[H^(+)]=(15)/(100)=0.15M`,
Also `p-log[H^(+]-log 0.15," "pH =0.8239`