Question

In acid-base titration react rapidly to neutralise each other. Equivalence point is a point at which the acid and the base (or oxidising agent and reducing agent) have beem added in equivalent quantities. The end point in the point at which the titration stops. since the purpose of the indicator is to stop the titration close to the point at which the acid and base were added in equivalent quantities, it is important that the equivalent point and the end point be as close as must change colour at a `pH` close to that of a solution of the salt of the acid base. Singificantly, the `pH` changes most rapidly near the equivalent point. The exact shape of a titration curve depends on `K_(a)` and `K_(b)` of acid and base.

The curve represents the titration of
A. `CsOH by HBr`
B. `HCI by NaOH`
C. `HCI by KOH`
D. `NH_(3) by HNO_(3)`

Answer 1

Correct Answer - A
Since the curve starts at higher `pH (12.5)`, so it should be strong base and `pH` changes most rapidly near the equivalence point, so it should be strong acid. Hence the titration is strong base with strong acid (i.e., `CsOH` by `HBr)`.