Question

The effect of temperature on equilibrium constant is expressed as`(T_(2)gtT_(1))`
log`K_(2)//K_(1)=(-DeltaH)/(2.303)[(1)/(T_(2))-(1)/(T_(1))]`. For endothermic, false statement is
A. `[(1)/(T_(2))-(1)/(T_(1))]="positive"`
B. `DeltaH="positive"`
C. log`K_(2)gt"log"K_(1)`
D. `K_(2)gtK_(1)`

Answer 1

Correct Answer - A
`"log K_(2)//"logK_(1)=(-DeltaH)/(2.303)[(1)/(T_(2))-(1)/(T_(1))] rArr DeltaH="positive"`