Question

Dissociation constant of acetic acid is 1.8 × 10^-5. Calculate percent dissociation of acetic acid in 0.01 M solution.

Answer 1

Given : K_a = 1.8 x 10^-5; C = 0.01 M

Percent dissociation = ?

\(\therefore\) Percent dissociation = α × 100

= 4.242 × 10^-2 × 10² 

= 4.242%

Percent dissociation = 4.242%