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Balance the following equation (i) KMnO4 + H2C2O4 + H2SO4 → MnSO4 + K2SO4 + H2O + O2

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Balance the following equation

(i) KMnO4 + H2C2O4 + H2SO4 → MnSO4 + K2SO4 + H2O + O2

(ii) K2Cr2O7 + Kl + H2SO4 → K2SO4 + Cr2(SO4)3 + 7H2O + 3l2

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(i) 2KMnO4 + 3H2SO4 + 5H2C2O4 → K2SO4 + 2MnSO4 + 8H2O + 10CO2 

(ii) Acidified potassium dichromate oxidises potassium iodide (KI) to iodine (I2). Potassium dichromate is reduced to chromic sulphate. Liberated iodine turns the solution brown

K2Cr2O7 + 6Kl + 7H2SO4 → 4K2SO4 + Cr2(SO4)3 + 7H2O + 3l2 [Oxidation state of iodine increases from – 1 to zero]

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