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Explain the variation of vapour pressure with mole fraction of a solute in a liquid mixture.

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Consider a liquid mixture of two liquid components A and B having vapour pressures \(P_1^0\) and \(P_2^0\) and mole fractions x1 and x2 respectively.

By Raoult’s law, 

The vapour pressures P1 and P2 are,

P1 = x1\(P_1^0\) and P2 = x2\(P_2^0\)

The vapour pressure of the solution is,

PT = P1 + P2 

= x1\(P_1^0\) + x2\(P_2^0\)

∴ PT = (\(P_2^0\) - \(P_1^0\))x2\(P_1^0\)

The plot of PT versus x2 is a straight line. The plots of P1 versus x1 and P2 versus x2 are straight lines passing through the origin.

When x1 = 1, x2 = 0, PT\(P_1^0\) and when x1 = 0,x2 = 1,PT\(P_2^0\) as shown by lines I and II in fig.

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