Calculate the weight of `N_(2)` in `6.24` litre cylinder at `27^(@)C` and `750 mm hg` `(R =0.0821` litre atm `K^(-1) mol^(-1))`

Correct Answer - 7
Given `V =6.24 litre, P = (750)/(760)atm`
`T = 27 + 273 = 300K, m = 28`
Now `PV = (w)/(m0RT)`
`:. W = (PVm)/(RT) = (750 xx 6.24 xx 28)/(760 xx 0.0821 xx 300) =7g` .

Calculate the weight of `N_(2)` in `6.24` litre cylinder at `27^(@)C` and `750 mm hg` `(R =0.0821` litre atm `K^(-1) mol^(-1))` .

Please log in or register to add a comment.

1 Answer

Please log in or register to add a comment.

Find MCQs & Mock Test

Related questions

Categories