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The weight of `350mL` of a diatomic gas at `0^(@)C` and 2 atm pressure is `1 g`. The weight in g of one atom at `NTP` is:

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The weight of `350mL` of a diatomic gas at `0^(@)C` and 2 atm pressure is `1 g`. The weight in g of one atom at `NTP` is:
A. `16//N`
B. `32//N`
C. `16 N`
D. `32 N`
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Correct Answer - A
Calculate `M=(RT.w)/(PV)` and then
`(M) g=2N "atoms"=N "molecules"`.
( `:.` Gas is diatomic)
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