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When the same amount of zinc is treated separately with excess of `H_(2)SO_(4)` and excess of `NaOH`, the ratio of volumes of `H_(2)` evolved is:
A. `1:1`
B. `1:2`
C. `2:1`
D. `9:4`

1 Answer

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Best answer
Correct Answer - A
`Zn+H_(2)SO_(4)rarrZnSO_(4)+H_(2)`,
`Zn+2NaOHrarrNaZnO_(2)+H_(2)`

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