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The equivalent weight of iron in `Fe_(2)O` would be:

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The equivalent weight of iron in `Fe_(2)O` would be:
A. `18.6`
B. `26.66`
C. `56`
D. `112`
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Correct Answer - A
`E_(Fe_(2)O_(3))=M//6` and `E_(Fe)=(at.wt)/(3)=(56)/(3)`
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