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How many mole of magnesium phosphate `Mg_(3)(PO_(4))_(2)` will contain `0.25 "mole"` of oxygen atoms?
A. `0.02`
B. `3.125xx10^(-2)`
C. `1.25xx10^(-2)`
D. `2.5xx10^(-2)`

1 Answer

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Best answer
Correct Answer - B
`8 "mole of" O-"atom"equiv"mole" Mg_(3)(PO_(4))_(2)`
`0.25"mole of" O-"atom"=(1xx0.25)/(8)`
`=3.125xx10^(-2)"mole of" Mg_(3)(PO_(4))_(2)`

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