Question

Calculate the compressibility factor for `SO_(2)` if 1 mole of it occupies 0.35 litre at `300K` and 50 atm pressure Comment on the result .

Answer 1

Compressibility factor `(Z) =(PV)/(nRT)`
`Z = (40 xx 0.4)/(1 xx 0.0821 xx 300) = 0.65`
Since `Z` value is lesser than 1 and thus , `nRT gtPV` In order to have `Z =1` volume of `CO_(2)` must have been more at same `P` and `T` or `Co_(2)` is more compressible than ideal gas .