A compound `(C_(5)H_(8))` reacts with ammoniacal `AgNO_(3)` to give a white precipitate and reacts with excess of `KMnO_(4)` solution to give `(CH_(3))_(2)CH-COOH`. The compound is
A. `CH_2=CH-CH=CHCH_3`
B. `CH_3(CH_2)_2C-=CH`
C. `(CH_3)_2CHC-=CH`
D. `(CH_3)_2C=C=CH_2`