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Arrange the following in the decreasing order of their boiling points:
I. `C_(9)H_(20)` II. `C_(8)H_(18)`
III. image
A. (a) `(I) gt (II) gt (III) gt (IV)`
B. (b) `(IV) gt (III) gt (II) gt (I)`
C. (c) `(I) gt (II) gt (IV) gt (III)`
D. (d) `(III) gt (IV) gt (II) gt (I)`

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Correct Answer - A
The greater the number of C atoms and straight chain, the higher is the boiling point. So, I is greater than II. More is the branching, less is the surface area, so lower is the boiling point. Therefore, III is greater than IV.

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