In the reaction:
`H_(2)C=CH-CH=CH_(2)underset(180^(@)C)overset(Br_(2))to[X]`, [X] will be
A. `BrCH_(2)-CH=CH-CH_(2)-Br`
B. `CH_(2)Br-CHBr-CH=CH_(2)`
C. `overset(Br)overset(|)(C)H_(2)-overset(H)overset(|)(C)=overset(Br)overset(|)(C)-CH_(3)`
D. `CH_(3)-overset(Br)overset(|)(C)=overset(Br)overset(|)(C)-CH_(3)`