Correct Answer - D
Reduction of `H_2O` takes place at cathode since reduction potential of `H_2Ogt` reduction potential of `K^(o+)` ions.
At anode 2 mole of `CO_2` + 1 mol of propyne gas is obtained by 2 faraday (since two `bare` are produced).
2 faraday `implies` 3 mol of gases under standard conditions (1 bar, 298K)
`implies 3xx 24.7` litres `=74.1` litres
So the answer is (d).