Question

Give reasons for the following:
`CH_2=CH^(Θ)` is more basic than `HC-=C^(Θ)`

Answer 1

`HC=C^(Θ)` is a conjugate base of `HC-=CH`.
`H_2C=CH^(ӫ)` is a conjugate base of `H_2C=CH_2`.
`HC-=CH` is more acidic than `H_2C=CH_2`.
As a rule, the stronger is the acid, the weaker is its conjugate base and vise versa.
So, `H_2C=CH^(ӫ)` is more basic than `HC-=C^(Θ)`.