Terminal alkyne is very weak acid, it forms salt with very strong base such as `NaNH_(2)` and sodium metal.
`R-C-=C-Hunderset(NH_(3)(l))overset(NaNH_(2))toR-C-=overset(ө)(C)overset(o+)(N)a+(1)/(2)H_(2)`
Sodium salt of alkyne is known as shown alkynide. sodium alkynide is hydrolysed with water because it is salt.
Sodium salt behaves as nucleophile as well as strong base. for P-alkyl halides it behaves as a cucleophile. thus primary alkylhalides gives SN reaction halids it behaves as strong base hence they undergo elimination reaction.
Q. `CH_(3)-overset(Br)overset(|)(C)H-CH_(3)overset(R-C-=overline(C)overset(+)(N)a)toS+T+Br^(-)` S and T are
A. `CH_(3)-CH_(2)-CH_(3),R-C-=CH`
B. `CH_(3)-CH=CH_(2),R-C-=CH`
C. `CH_(3)-CH=CH_(2),R-CH_(2)-CH_(3)`
D. `CH_(3)-C-=CH,R-C-=CH`
