Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
469 views
in Chemistry by (67.3k points)
closed by
(a) `[BeF_(4)]^(2-)` exits, but `[BeCl_(6)]^(4-)` does not. Give reson.
(b). Hydrated beryllium ion exists as `[Be(H_(2)O)_(4)]^(2+)`, whereas hydrated magnesium ion exists as `[Mg(H_(2)O)_(6)]^(2+)`. Give reason.

1 Answer

0 votes
by (69.5k points)
selected by
 
Best answer
a. `[BeF_(4)]^(2-)` exists, but `[BeF_(6)]^(4-)` does not. This can be explained on the basis of valence electronic configuration:
image
Due to the absence of low-lying `d`-orbitals in beryllium, it cannot expand its coordination number beyond`4`, hence `[BeF_(4)]^(2-)` exists, but `[BeF_(6)]^(4-)` does not.
b. Hydrated beryllium ion exists as `[Be(H_(2)O)_(4)]^(2+)`.
image
Due to the presence of only four orbitals of equivalent energy in `Be^(2+)` ion and due to the absence of low-lying `d-`orbitals in `Be^(2+)` ion, it can coordinate with four water molecules only, hence hydrated beryllium ion exists as `[Be(H_(2)O)_(4)]^(2+)`.
Whereas in case of magnesium, due to the availability of low-lying d-orbitals of suitable energy, `Mg` can expand its coordination number to 6
image
Hence, hydrated magnesium ion exists as `[Mg(H_(2)O_(6))]^(2+)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...