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The degree of dissociation of ammonium hydroxide is 0.0232 in 0.5 M solution. What will be the dissociation constant of ammonium hydroxide?

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Given : 

Degree of dissociation = α = 0.0232 

Concentration of NH4OH = C = 0.5 M 

Dissociation constant = Kb = ?

Kb = Cα2

= 0.5 × (0.0232)2

= 2.692 × 10-4

∴ Dissociation constant of NH4OH = Kb = 2.692 × 10-4

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