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In the adjoining figure, A – D – C and B – E – C. seg DE || side AB. If AD = 5, DC = 3, BC = 6.4,

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In the adjoining figure, A – D – C and B – E – C. seg DE || side AB. If AD = 5, DC = 3, BC = 6.4, then find BE.

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 In ∆ABC, 

seg DE || side AB [Given]

\(\therefore\) \(\frac{DC}{AD} = \frac{EC}{BE}\) [Basic proportionality theorem]

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