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∆LMN ~ ∆PQR, 9 × A(∆PQR) = 16 × A(∆LMN). If QR = 20, then find MN.

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9 × A(∆PQR) = 16 × A(∆LMN) [Given]

Now, ∆LMN ~ ∆PQR [Given]

[Theorem of areas of similar triangles]

∴ MN/QR = 3/4 [Taking square root of both sides]

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