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When `CH_(2) = CH - COOH` is reduced with `LiAlH_(4)`, the compound obtained will be
A. `CH_(3) - CH_(2) - COOH`
B. `CH_(2) = CH - CH_(2)OH`
C. `CH_(3)CH_(2) - CH_(2)OH`
D. `CH_(3) - CH_(2) - CHO`

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Correct Answer - B
When `CH_(2) = CH - COOH` is reduced with `LiAlH_(4) : CH_(2) = CH - CH_(2)OH` compound is formed because `LiAlH_(4)` reduces `-COOH` to `CH_(2)OH` without affecting `C = C` bond

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