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When propanamide reacts with `Br_(2)` and NaOH then which of the following compounds is formed ?

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When propanamide reacts with `Br_(2)` and NaOH then which of the following compounds is formed ?
A. Ethyl alcohol
B. Propyl alcohol
C. Propyl amine
D. Ethylamine
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Correct Answer - D
`CH_(3)CH_(2)CONH_(2) underset(underset("reaction")("Hoffmann bromamide"))overset(Br_(2) //KOH)(rarr) underset("Ethylamine")(CH_(3)CH_(2)NH_(2))`
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