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`CH_(3)COCl` on reaction with hot alcoholic potash gives
A. `CH_(3)COOH`
B. `CH_(2) = C = O`
C. `CH_(3)COO^(-)K^(+)`
D. `(CH_(3)CO)_(2)O`

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Correct Answer - B
`CH_(3)COCl` on reaction with hot alcoholic potash undergoes loss of `HCl` to form ketene `CH_(2) = C = O`
`CH_(3) - COCl + KOH (alc.) overset(Delta)rarr underset("Ketene")(CH_(2) = C = O) + KCl + H_(2)O`

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