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The ratio between the root mean square speed of `H_(2)` at `50 K` and that of `O_(2)` at `800 K` is
A. `4`
B. `2`
C. `1`
D. `1//4`.

1 Answer

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Best answer
Correct Answer - C
`U_(rms)(H_(2)) =sqrt((3RT_((H_(2))))/(M_((H_(2)))))`
`U_(rms)=sqrt((3RT_((O_(2))))/(M_((O_(2)))))`
`(U_(rms)(H_(2)))/(U_(rms)(O_(2))) = sqrt((T_((H_(2))))/(M_((H_(2))))xx (M_(O_(2)))/(T_(O_(2))))`
`=sqrt((50 xx 32)/(2 xx 800)) = 1`.

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