Correct Answer - B
`H_(3)C-CH=CH_(2)-OH underset(("Red"))overset(Br_(2)//C Cl_(4))rarr H_(3)C-underset(("Colourless"))(underset(Br)underset(|)(CH)-underset(Br)underset(|)(CH))-CH_(2)-OH`
`H_(3)C-CH=CH-CH_(2)OH overset(PCl_(5))rarr HCl+POCl_(3)+H_(3)C-CH=CH-CH_(2)-Cl`