Question

The density of a gas is found to be `1.56 g dm^(-3)` at `0.98` bar pressure and `65^(@)C`. Calculate the molar mass of the gas.

Answer 1

From the available data :
`rho = 1.56 g dm^(-3) , P = 0.98 "bar"`
`T = (65+273) = 338 K, R = 0.083 dm^(3) "bar" K^(-1) mol^(-1)`.
We know that, `M = (rhoRT)/(P) = ((1.56 g dm^(-3)) xx (0.083 dm^(3) "bar" K^(-1) mol^(-1)) xx (338 K))/((0.98 "bar"))`
`= 44.66 g mol^(-1)`