Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
73 views
in Chemistry by (62.2k points)
closed by
(a) How does bond energy vary from `N_(2)^(+)` and `N_(2)^(-)` and why ?
(b) On the basis of the molecular orbital theory, what is the similarly between :
`(i)F_(2),O_(2)^(2-)" "(ii)CO,N_(2),NO^(+).`
(c ) Like CO why its analong SiO is not so stable ?

1 Answer

0 votes
by (61.5k points)
selected by
 
Best answer
(a) Both `N_(2)^(+) and N_(2)^(-)` have same bond order (2.5). Hence both have the same energy.
(b) (i) Both `F_(2),O_(2)^(2-)` are isoelectronic. They have the same molecular orbital configuration as well as the bond ordre.
(ii) CO, `N_(2),NO^(+)` have the same bond order (3.0).
(c ) In Co, thereis multiple bonding present. `(Coverset(larr)(=)O":").` As result, it is quite stable. On the other hand, silicon (Si) atom due to is large size linked to oxygen by single bond only (Si-O). Therefore, it is not so stable.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...