Question

The hybridization of atomic orbitals of nitrogen is `NO_(2)^(+), NO_(3)^(-)`, and `NH_(4)^(+)` respectively are
A. `sp,sp^(3),and sp^(2)` respectively
B. `sp,sp^(2),and sp^(3)` respectively
C. `sp^(2),sp,and sp^(3)` rspectively
D. `sp^(2),sp^(3),and sp` respectively

Answer 1

Correct Answer - B
`NO_(2)^(+)=1//2[5+0-1+0]=4//2=sp`
`NO_(3)^(-)=1//2[5+0-0+1]=6//2=sp^(2)`
`NH_(4)^(+)=1//2[5+4-1+0]=8//4=sp^(3)`