Correct Answer - b
`EtS^(o-) ` Is more nuscleophiklic the n `EtO^(0-)`
(A) `CH_(3)-CH_(2)-O^(-)gtCH_(3)-CH_(2)-OH"changed "Nu^(-)` better than neutral .
more stable T.S because fo more bionding due to large size .
(C ) Rate of `S_(N^(2)) alpha ["substate"][NU^(-)]`
It is equal for both 1 nan d2 .
(d)` ph_(3) Pgt ph_(3) n`
`Et-overset(0+)P ph_(3) gt Et - overset(0+) N ph_(3) ` more stable because more change dispersion on larger atom.