Question

Calculate the mass of sodium acetate `(CH_(3)COONa)` required to make `500 mL` of `0.375` molar aqueous solution. Molar mass of sodium of acetate is `82.0245 g mol^(-1)`.

Answer 1

0.375 M aqueous solution od sodium acetate
`-=` 1000 mL of solution containing 0.375 moles of sodium acetate
`therefore ` Number of moles of sodium aceate in 500 ml
`=(0.375 )/(1000)xx500`
`=0.1875 ` mole
Molar mass of sodium acetate = 82.0245 g `"mole"^(-1)` (Given )
`therefore ` Required mass of sodium acetate `=(82.0245 g mol ^(-1) ) (0.1875 "mole")`
=15.38 g

Comments

Answer is correct it makes my marks in chemistry