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`3Cu + 8HNO_(3) rarr 3Cu (NO_(3))_(2) +2NO +4H_(2)O` the wrong statement for the value

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`3Cu + 8HNO_(3) rarr 3Cu (NO_(3))_(2) +2NO +4H_(2)O` the wrong statement for the value
A. `Cu` is oxidized
B. `HNO_(3)` is reduced
C. `Cu` is reduced
D. `Cu` acts as reducing agent
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Correct Answer - C
O.S of Cu increase From oto `+2`
`:.` cu oxidised
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