Question

What will be the molarity of a solution, which contains 5.85g of `NaCl(s)` per 500mL?
A. 4 mol `L^(-1)`
B. 20 mol `L^(-1)`
C. 0.2 mol `L^(-1)`
D. 2 mol `L^(-1)`

Answer 1

Molarity (M) `=("No. of moles of solute")/("Volume of solution (in L)")`
or Molarity `=(W_Bxx1000)/(M_Bxx"Volume of soution (in mL)")`
`=(5.85xx1000)/(58.5xx500) ( therefore` molar mass of NaCl = 58.5g `mol^(-1)`)
`=0.2mol L^(-1)`