Correct Answer - B
`C_(3)H_(8) +5O_(2) rarr 3CO_(2)+4H_(2)O`
x litres of propane produce `3x` litre of `CO_(2)`
`C_(4)H_(10) +6.5O_(2) rarr 4CO_(2) +5H_(2)O`
(3-x) litres of butane produce `4(3-x)` lit of `CO_(2)`
`3x +4 (3-x) = 11, 3x + 12 - 4x = 11`
`12 - x = 11, x = 1` litre
volume of butane: propane `= 2:1`