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Calculate the temperature of 4.0 mol of a gas occupying d `dm^(3)` at 3.32 bar. (R=0.083 bar `dm^(3) K^(-1)mol^(-1))`.

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Correct Answer - 50 K
Given, n = 4.0 mol
V= 5 `dm^(3)`
p = 3.32 bar
R= 0.083 bar `dm^(3)K^(-1)mol^(-1)`
The temperature (T) can be calculated using the ideal gas question as:
pV = nRT
`rArrT=(pV)/(nR)`
`=(3.32xx5)/(4xx0.083)`
= 50 K
Hence, the required temperature is 50 K.

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