Correct Answer - A
`{:(3Br_(2)+6OH^(-)rarr,5Br^(-)+,BrO_(3)^(-)+3H_(2)O),(0,-1,+5):}`
`6H^(+) +BrO_(3)^(-) +3C_(2)O_(4)^(2-) rarr Br^(-) +6CO_(2)+3H_(2)O`
10m. Mole `Br_(2) rarr 10//3`m. mole of `BrO_(3)^(-)`
`rArr 10ml`. mol of `C_(2)O_(4)^(2-)`
% purity `=(10 xx 10^(-3) xx 128)/(1.5) = 100 = 85.3`