Correct Answer - A::C::D
`MnO_(4)^(-) overset(H^(+))rarr Mn^(2+)` (n-factor =5)
m eqts of `MnO_(4)^(-)` used `=25 xx 0.2 = 5`
(A) m eqts of `FeSO_(4) = 25 xx .2 = 5`
(B) m eqts of `H_(3)AsO_(3) = 50 xx 0.2 = 10`
`[H_(3)AsO_(3) rarr H_(3)AsO_(4)` (n-factor =2)
(C) m eqts of `SO_(3)^(2-) -= 25 xx 0.2 = 5`
`[SO_(3)^(2-) rarr SO_(4)^(2-)`, n-facor =2]
(D) m.eqts of `SnCl_(2) = 25 xx 0.2 = 5`
`[Sn^(2+) rarr Sn^(4+)`, n-factor =2]