Question

`H_(2)overset(14)(C)=CH-CH_(3)overset("low conc. of "Br_(2))underset("or high temp")(to)(?)`
Product of the above reaction is:
A. `H_(2)overset(14)(C)=CH-CH_(3)-Br`
B. `H_(2)C=CH-overset(14)(CH_(2))-Br`
C. `overset(14)underset(Br)underset(|)(C)H_(2)-underset(Br)underset(|)(C)H-CH_(3)`
D. Both (a) and (b)

Answer 1

Correct Answer - d
Low conc. Of `Br_(2)` and high temperature favour substitution reaction, proceed through free radical.
`therefore` Substitutaion will be major product.