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`3.0gms` of an organic compound on combustion give `8.8 gm` of `CO_(2)` and `5.4gm` of water. The empirical formula of the compound is

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`3.0gms` of an organic compound on combustion give `8.8 gm` of `CO_(2)` and `5.4gm` of water. The empirical formula of the compound is
A. `CH_(3)`
B. `C_(2)H_(4)`
C. `C_(2)H_(2)`
D. `C_(2)H_(6)`
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Correct Answer - A
`C_(x)H_(y)+ (x+(y)/(4)) O_(2) rarr xCO_(2) +(y)/(2) H_(2)O`
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