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What will be the normally of a solution obtained by mixiing 0.45N and 0.60N NaOH in the ration 2:1 by volume?
A. `0.5g`
B. `25g`
C. 20g
D. 5g

1 Answer

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Best answer
Correct Answer - C
`N = (V_(1)N_(1)+V_(2)N_(2))/(V), N = (w)/(GEW) xx (1)/(V("in lits"))`

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